Question

If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s2, how long will it take to come to rest? Also find out the distance covered by the bus during this time.

Answer 1

Explanation:

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Answer 2

Answer:

u=20m/s

a= - 5m/s²

v=0

t=?

a=v-u/t

-5=0-20/t

-5=-20/t

t= - 20/-5

=4 sec

Hence, time is 4 seconds.

Now,

V=20m/s

t=4s

S=?

V=s/t

20=s/4

20×4=s

s=80

Hence, the distance traveled is 80m/s