if a bus travelling at 20 m/s is subjected to steafy deceleration of 5 ms/2 how long will it take to come at rest
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Answered by
0
u=20m PS
a=-5ms/,2
a=v-u/t
-5=0-20/t
then t=4s
a=-5ms/,2
a=v-u/t
-5=0-20/t
then t=4s
Answered by
1
v = u + at
0 = 20 + (-5)t
t = 4 seconds
It will take 4 second to come to rest.
0 = 20 + (-5)t
t = 4 seconds
It will take 4 second to come to rest.
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