if a bus travelling at 20m/s os subjected to steady deceleration of 5m/ssquare how much willit take to come to rest
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the bus come to rest at 4th half in which the travel
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deaccleration(a)=5 m/s square
initial velocity (u)=20m/s
final velocity(v)=0m/s
by using first equation of motion,
v=u+at
0=20+(-5)*t
-20/-5=t
4 seconds =t
it will take 4 seconds to come to rest..
hope it helps nd mark it as brainlest
initial velocity (u)=20m/s
final velocity(v)=0m/s
by using first equation of motion,
v=u+at
0=20+(-5)*t
-20/-5=t
4 seconds =t
it will take 4 seconds to come to rest..
hope it helps nd mark it as brainlest
Ananya09:
mark it as brainlest
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