Question

If a bus travels from city A to city B with a speed of 567 kmph and another bus travels from city B to city A with a speed of 477 kmph, find the relative speed when both the buses cross each other. (in m/s)​

Answer 1

Answer:

Step-by-step explanation:

Relative speed = 567+477 = 1044 kmph

RS = 1044x 1000/3600 m/s

RS = 1044 x 5/18 m/s

RS = 290 m/s

Answer 2

Given,

Speed of the bus traveling from city A to city B = 567 kmph

Speed of the bus traveling from city B to city A = 477 kmph

To find,

The relative speed in m/s, when both the buses cross each other.

Solution,

We can simply solve this numerical problem by using the following process:

As per the concepts of linear motion;

As per the concepts of linear motion;When two objects are moving towards each other, then their relative speed is equal to the sum of the individual speeds of the two objects.

Now,

The relative speed in m/s, when both the buses cross each other

= Speed of the bus traveling from city A to city B + speed of the bus traveling from city B to city A

= 567 kmph + 477 kmph

= 1044 kmph = 1044 Km/hr

= (1044x1000/3600) m/s

= 290 m/s

Hence, the relative speed when both the buses cross each other is equal to 290 m/s.