If a+c=2b, prove that a/(a-b) + c/(c-b) = 2
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Step-by-step explanation:
Given, a+c=2b => c= 2b-a
replace c by 2b-a
a/(a-b)+c/(c-b) = a/(a-b)+(2b-a)/(2b-a-b)
= a/(a-b)+(2b-a)/(b-a)
= a/(a-b)+(a-2b)/(a-b)
= (a+a-2b)/(a-b)
= (2a-2b)/(a-b)
= 2(a-b)/(a-b)
= 2
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