Math, asked by sulemandalal, 5 months ago

If
A+C=4
D+E=9
B+F=8
Z+C=29
THEN,
G+A=???​

Answers

Answered by sardarahmedsafeer
1

Answer:

37

Step-by-step explanation:

A+C=4

D+E=9

B+F=8

Z+C=29

THEN,

G+A=???

Answered by Anonymous
3

Answer:

8

Step-by-step explanation:

A - 1st alphabet - take it as 1

B - 2nd alphabet - take it as 2

C - 3rd alphabet - take it as 3

D - 4rd alphabet - take it as 4

E - 5rd alphabet - take it as 5

F - 6rd alphabet - take it as 6

G - 7rd alphabet - take it as 7

H - 8rd alphabet - take it as 8

I - 9rd alphabet - take it as 9

J - 10rd alphabet - take it as 10

A + C

1 + 3 = 4

So, A + C = 4

D + E

4 + 5 = 9

So, D + E = 9

B + F

2 + 6 = 8

So, B + F = 8

Similarly,

Z + C = 29

G + A

7 + 1 = 8

Therefore, G + A = 8

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