Question

If a + c = 4b then the roots of a * x ^ 2 + 4bx + c = 0 are​

Answer 1

Answer:

Step-by-step explanation:

∵(4a+c)  

2

⩽4b  

2

 

⇒4a+c⩽±2b  

⇒4a±2b+c⩽0

∴4a+2b+c⩽0  

or , 4a−2b+c⩽0

let f(x)=ax  

2

+bx+c

∴f(2)=4a+2b+c≤0  

f(−2)=4a−2b+c≤0

Case 1 :- a>0                

Case 2 :- a<0  

∴ Roots should lie between (−2,2)