If a+c=b then find the value of a³+b³+3abc=b³
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Answer:
To find : a³ + b³ + 3abc = b³ ; Given : a + c = b - (1)
Step-by-step explanation:
solution :. a + c = b
( Taking cube on both the sides )
( a + c )³ = b³
a³ + c³ + 3ac(a+c) = b³. [ using property ( x+y)³]
a³ + c³ + 3acb = b³ [ As from (1) a + c = b, substituting value ]
Hence Proved, a³+c³+3abc = b³
- OR -
Solution : a³ + b³ + 3abc = b³
subtracting b³ on both sides
a³ + b³ - b³ + 3abc = b³ - b³
a³ + 3abc = 0
substituting value of 'b' from 1
a³ + 3ac( a + c ) = 0
a³ + 3a²c + 3ac² = 0
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