if a=c^z, b=a^x, c=b^y prove that xyz=1
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Answered by
5
ax=b => x=logab
by=c=> y=logbc
cz=a=> z=logca
xyz=(logab.logbc).logca
=logac.logca
=logaa
=1
I hope it is useful for you ......
by=c=> y=logbc
cz=a=> z=logca
xyz=(logab.logbc).logca
=logac.logca
=logaa
=1
I hope it is useful for you ......
Answered by
4
Given a=c^z, b=a^x, c=b^y
a=b^yz
b=b^xyz
b^1=b^xyz
xyz=1
a=b^yz
b=b^xyz
b^1=b^xyz
xyz=1
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