If a=c^z;b=a^x;c=b^y, prove x*y*z=1
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Step-by-step explanation:
a=c^z
log a= z log c
z=log a/ logc..................(1)
****************************
b=a^x
log b=xlog a
x=log b/ log a......................(2)
****************************
c=b^y
log c=y log b
y = log c/log b...............................(3)
On multiplying(1),(2) and (3) we get
x*y*z= ( log a/ logc)*( log b/ log a)*(log c/ logb)
=1
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