Question

if A can complete a work in 10 days and B can complete the same work in 12 days individually, then how many days will the work get completed if the work simultaneously.​

Answer 1

Answer:

In $\frac{60}{11}$ days ,the work get completed if the work simultaneously.​

Step-by-step explanation:

Given,

         A can complete a work in 10 days.

         A can complete work in one day=$\frac{1}{10} work$

          B can complete the same work in 12 days

          B can complete work in one day=$\frac{1}{12} work$

A and B will do work in a day=

                                            $\frac{1}{10}+\frac{1}{12}$

L.C.M between 10 and 12 is 60

              $=\frac{6+5}{60} \\ \\ =\frac{11}{60}$

        So together they can complete work in $=\frac{60}{11}$ days.

 

Answer 2

Step-by-step explanation:

Given,

A can complete a work in 10 days.

A can complete work in one day=\frac{1}{10} work

10

1

work

B can complete the same work in 12 days

B can complete work in one day=\frac{1}{12} work

12

1

work

A and B will do work in a day=

\frac{1}{10}+\frac{1}{12}

10

1

+

12

1

L.C.M between 10 and 12 is 60

\begin{gathered}=\frac{6+5}{60} \\ \\ =\frac{11}{60}\end{gathered}

=

60

6+5

=

60

11