Math, asked by sumitchauhan9956, 3 months ago


If A can do as much work in 4 hours as B can do in 6 hours or as C can do in 8 hours. They
started work together for 1 hr after that they work alternately hour by hour starting with Afollowed
by B and C. In how many hours will the total work be finished?​

Answers

Answered by sahuayushman10
0

Answer:

Let qty.of work done by A in 4 hrs be x.

So part of work done by A in 1hr =x/4

Part of work done by B in 1 hr = x/6

Part of work done by C in 1 hr = 1/8

Part of work done by A working 8 hrs.and B working 18 hrs. = 8(x/4)+18(x/6)

= 2x + 3x = 5x

No.of days taken by C to finish x part=8

So no.of days taken by C to finish 5x part

= 5×8 = 40 hrs

ie.no.of days taken by C to finish 1/3 of the work = 40 hrs.

So no.of hrs.takem by C to finish the work = 3×40 = 120 hrs.

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