Question

if a candidates a,b,c is a 3 school election got 153,245 and 102 votes respectively the percentage of votes for the winner is ?​

Answer 1

Answer:

49%

Step-by-step explanation:

Total voters = 500

The winner is candidate B seeing as they got the most votes out of them all

$\frac{245}{500} =\frac{x}{100}$

This equation shows the value of votes in a ratio to the total on the left side and on the right compares it to a value over 100, which will lead to a percentage.

Solving algebraically through cross multiplication for x, you find that it gives you your answer --> 49.  

Answer 2

Answer:

Step-by-step explanation:

B is the winner

total votes =153+245+102 =500

percentage of B =245$/$500 × 100 =49

∴percentage of B =49%

THANK ME & MARK AS BRAINLIEST