if a cap + b cap and 5 ICAP - 4 b cap are perpendicular find angle between a cap and b cap
Answers
Answered by
32
Solution is in the attachment.
Attachments:
Answered by
7
As the two vectors are perpendicular,
Their dot product is zero
(a+2b)(5a-4b)=0
5a^2+6abcos(theta)-8b^2=0 (costheta is angle between acap and bcap)
As you mentioned acap and bcap, it means that they are unit vectors and have magnitude 1.
5+6costheta-8=0
Costheta=3/6=1/2
Theta=pi/3 or 60 degrees
Similar questions