if a capacitor is charged, battery remains connected and the space between the plates is filled with a dielectric constant K, what will happen in (I) charge stored (II) potential difference (III) capacitance (iv) electric field (v) energy stored in the capacitor
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the charge will become k times. voltage will be same the capacitance will increase by K times electric field will be same and the energy stored in a capacitor will be same
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