Question

If a capacitor of 10uF is charged with p.d. 5V, then
charge on it:-
(a) 50 C (b) 5x10-6C (c) 5x10-5C (d) 20​

Answer 1

Answer:

Answer:

Q=5×10^-5C

Given:

Potential difference, V=5V

Capacitance,C=10μF

Solution:

As we know that,

1μF=1×10^-6F

So, Capacitance=10×10^-6F

So,

Charge on the capacitor is,

Q=CV

Q=10×10^-6×5

Q=5×10^-5F

Explanation:

Hope it helps you....