if a capacitor of capacitance 10^2/π μF is connected across 220V, 50Hz A.C, the capacitive reactance is
a) 1000 ohm
b) 100 ohm
c) 10 ohm
d) zero
WITH EXPLANATION
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2
Answer
RMS value of applied voltage = 200 V
Impedance of a capacitor is given by:
X
C
=
2πfC
1
Hence, rms current through it is:
I=
X
C
V
I=200×2×π×50×10×10
−6
I=0.2π A
Peak current, I
max
=
2
I
=0.628
2
A
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