if a car accelerates in formerly from rest and attains a speed of 40 metre per second in 10 second it cover a distance of
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hey a .
v=u+at , u=0, v=40 ,a=? , t=10sec
40=a*10
a=4m/s^2
,,,,,,,,,,,,,,,,,,,,,
by using second equation
x=u+1/2at^2
x=0+1/2*4*100
x= 200m
hope it helps
v=u+at , u=0, v=40 ,a=? , t=10sec
40=a*10
a=4m/s^2
,,,,,,,,,,,,,,,,,,,,,
by using second equation
x=u+1/2at^2
x=0+1/2*4*100
x= 200m
hope it helps
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