Question

If a car accelerates uniformly from 5m/s to 10m/s in 5 seconds, the distance covered by the car is 12.5 m 17.5 m 13.5m 16.5m​

Answer 1

Answer:

37.5

Explanation:

Using Newton's third equation of motion i.e.

v² - u² = 2as

For this problem :

Final velocity (v) = 10 m/s

Initial velocity (u) = 5 m/s

Constant Acceleration (a) = ∆v/∆t = (10–5)/5

Hence a = 1 m/s²

Substituting these values in the equation :

10² - 5² = 2 *(1) s

75 = 2 s

s = 37.5 m

Answer 2

Given - Uniform acceleration from 5m/s to 10m/s Time taken - 5 seconds

Find - Distance covered by car

Solution - Firstly calculate the accelaration of the car using the formula v = u + at.

Calculating acceleration = v - u/t

Acceleration = 10 - 5/5

Acceleration = 5/5

Acceleration = 1 m/s²

Distance covered by car can be calculated by the formula v² - u² = 2aS. S represents the distance covered by the car.

Keeping the values to find the distance covered.

10² - 5² = 2*1*S

S = 100 - 25/2

S = 75/2

S = 37.5 metre

Hence, the distance covered by a car is 37.5 metres.