Question

if a car at rest accelerate uniformly and attains a speed of 72 km per hour in 10s then it covers a distance of
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Answer 1

Answer:

The distance covered is 100 metres

Explanation:

The velocity of car at rest = 0m/s

Therefore, initial velocity is 0m/s

Final velocity is 72km/h = 20m/s

Time taken = 10s

Therefore, acceleration = v-u/t

                                 =  20-0/10 = 2m/s^2

We want to find the distance,

the suitable formula is

s = ut + 1/2at^2

s = 1/2 * 2 * 10*10

s = 100m

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