Question

if a car at rest accelerates uniformly to a speed of 144 km/h in 20s , it covers a distance of

Answer 1

Given :

The initial velocity of the car = u = 0

The final velocity of the car = v = 144 km/h = 144×5/18 = 40 m/s

Then,

We have to find the distance covered by it in 20 s .

First we need to find its acceleration then we can easily find the distance covered :

using the equation ,

v = u + at

40 = 0 + a(20)

a = 40/20 = 2 m/s

Acceleration = 2m/s

Then ,

Using the equation,

s = ut + ½ at²

= 0×20+½×2×(20)² = 0+400 = 400 m

The required distance travelled by it = 400 m