Question

If a car at rest acceleration uniformly to a speed of 144km/h in 20 seconds,it cover distance of
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Answer 1

Answer: 400m

Explanation:

144km/hr =(144*5/18)m/sec=40m/sec

U=0,v=40m/sec,t=20sec

Applying first equation of motion,

V=u+at

40m/sec=a(20sec)

a=2m/sec²

Applying second equation of motion,

S=at²/2=2*(20)²/2=400m