If a car attains 36 km/h from rest in 12 minutes time, what is the distance covered?
PinkyTune:
Given, s= 36 km/hr
Answers
Answered by
32
so 12 min = 12 x 60 = 720 sec
36 km/h = 36 x 5/18 m/s = 10 m/s
v = u + at
⇒ 10 = 0 + a x 720
⇒ a = 10/720
so using s = u + at²/2
s = 0 + (10 x 720 x 720)/(720 x 2 )
⇒ s = 3600 m = 3.6 km
where symbol have their usual meanings
36 km/h = 36 x 5/18 m/s = 10 m/s
v = u + at
⇒ 10 = 0 + a x 720
⇒ a = 10/720
so using s = u + at²/2
s = 0 + (10 x 720 x 720)/(720 x 2 )
⇒ s = 3600 m = 3.6 km
where symbol have their usual meanings
Answered by
12
12 min = 12 x 60 = 720 sec
u=0(because car started from rest)
multiply the speed with to change it into the unit m/s
36 km/h =
velocity(v)=10
we know
v = u + at
[tex]10=0+a*time \\ 10=720*a a=10/720=1/72 m/s²[/tex]
s = ut + at²/2
s=total distance
=[tex]=0*720+ \frac{1}{2}* \frac{1}{72} *720 ^{2} \\ \\ =0+3600 \\ s=3600 m \\ [/tex]
total distance=3600 m
u=0(because car started from rest)
multiply the speed with to change it into the unit m/s
36 km/h =
velocity(v)=10
we know
v = u + at
[tex]10=0+a*time \\ 10=720*a a=10/720=1/72 m/s²[/tex]
s = ut + at²/2
s=total distance
=[tex]=0*720+ \frac{1}{2}* \frac{1}{72} *720 ^{2} \\ \\ =0+3600 \\ s=3600 m \\ [/tex]
total distance=3600 m
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