if a car attains a speed of 36km /h from rest in 12 minutes, what is the
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u=0 km/h
v=36km/h
t=12 min
36 km/h in m/s
36×5/18=10 m/s
t=12×60=720 sec
By using first equation
v=u+at
10=0+a×720
a=10/720
=1/72 m/s^2
Finding distance by using 3rd equation
v^2-u^2=2as
10^2-0^2=2×1/72×s
100=s/36
s=3600 m=3.6 km
꧁ʜᴏᴘᴇ ɪᴛs ʜᴇʟᴘs꧂
v=36km/h
t=12 min
36 km/h in m/s
36×5/18=10 m/s
t=12×60=720 sec
By using first equation
v=u+at
10=0+a×720
a=10/720
=1/72 m/s^2
Finding distance by using 3rd equation
v^2-u^2=2as
10^2-0^2=2×1/72×s
100=s/36
s=3600 m=3.6 km
꧁ʜᴏᴘᴇ ɪᴛs ʜᴇʟᴘs꧂
Answered by
1
Answer:
3.6 km
If a car attains a speed of 36 km /h from rest in 12 minutes, then the distance covered is 3.6km.
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