if a car attains a speed of 36km/h from rest in 12 minutes . what is the distance covered
Answers
Answered by
1
u=0
v=36km/h=10m/s
t=12min=720sec
a=v-u/t
a=10-0/720
a=1/72
now,
s=ut+1/2at×t
s=0+1/2×1/27×518400
s=1/54×518400
s=9600
v=36km/h=10m/s
t=12min=720sec
a=v-u/t
a=10-0/720
a=1/72
now,
s=ut+1/2at×t
s=0+1/2×1/27×518400
s=1/54×518400
s=9600
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Answered by
1
u=0km/hr
v=km/hr
t=12min=12/60hr=0.2hr
v=u+at :1 equation of motion
36=0+at
0.2a=36
a=36/0.2
a=36×5
a=180km/hr^2
s=ut+at^2/2
s=0+180×(0.2)^2/2
s=180×0.04/2
s=180×0.02
s=36km
total distance=36km
v=km/hr
t=12min=12/60hr=0.2hr
v=u+at :1 equation of motion
36=0+at
0.2a=36
a=36/0.2
a=36×5
a=180km/hr^2
s=ut+at^2/2
s=0+180×(0.2)^2/2
s=180×0.04/2
s=180×0.02
s=36km
total distance=36km
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