If a car covers 2/5th of the total distance with v, speed and
3/5th distance with v, then average speed is
(b) IT v2
2V,V2
(C) v + V2
5v, V2
(d) 3v, +2V2
step by step solution
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Explanation:
let X be the distance then
T1=(2/5x)/v
T2=(3/5X)/v
speed=distance/time
=X/t1+t2
X/(2/5X)/v+(3/5X)/v
=v
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