if a car covers 2/5th of the total distance with v1 speed and 3/5th distance with v2 then avg speed is?
Answers
Let the distance to be covered = 5 units.
Fraction of the journey covered at v speed= 2/5.
Distance covered at v speed = 2 units
Time taken to cover 2 units at v = 2/v units of time
Fraction of journey covered at v' speed= 3/5
Distance covered at v’speed= 3 units.
Time taken to cover 3 units at v'= 3/v’ units of time.
Total time taken to cover 5 units of journey= (2/v)+(3/v')= (2v’ + 3 v)/vv'
Average speed = total distance covered ÷ total time taken = 5 ÷ ( 2v’ + 3 v)/vv'= 5 v v'/ (2v’ + 3v)
Answer:
Average speed is = ( 5 v1 v2 ) / ( 3v1+2v2)
Explanation:
we know the formula for average speed = total distance travelled / total time taken
=> let the total distance travelled be = 2s/5 +3s/5 = s
average speed = s / [ t1 + t2 ]
we know that time = distance / speed
time t1 = 2s/5v1 and time t2 = 3s/5v2
=> average speed = s / [ 2s/5v1 + 3s/5v2 ]
by calculating average speed = ( 5 v1 v2 ) / ( 3v1+2v2)