Question

if a car covers 2/5th of the total distance with v1 speed and 3/5th distance with v2 then aerage speed is

Answer 1

Vav
$average \: velocity = \frac{ \frac{2}{5} s + \frac{3}{5} s}{ \frac{2s}{5 \times v1} + \frac{3s}{5v2} }$

Solving 5V1V2/(2V2+3V1)

Answer 2

Answer:

Explanation:

Average speed = total distance by total time

A person covered 2/5th of the distance with speed V1

Left 3/5th distance was covered with speed V2

So,total distance is 5 units

Total time = total distance / speed

= 2/V1 + 3/ V2

Average speed = 5 / 2V1 + 3x2

= 5V1 V2 / 2V2 +3V1