if a car covers 2/5th of the total distance with v1 speed and 3/5th of the total distance with v2 speed, then average speed of the car is
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Answered by
35
hi.................
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dewangSINGLA:
here speed is given
so avg. speed is same to avg. velocity
thnx
according to the question
Answered by
2
Answer:
5v1*v2/(3*v1+2*v2)
Explanation:
average velocity= total displacement/total time
distance = x
time1=(2/5x)/v1
time2=(3/5x)/v2
average velocity=x/((2/5x)/v1)+((3/5x)/v2)
=x/1/5x(2/v1+3/v2)
(only brackets solving)=(2v2+3v1)/v1v2
x*5/x (v1v2)/(3v1+2v2)
=5v1v2/(3v1+2v2)
hope it helps
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