if a car decelerates from 40 m per second to 10 metre per second in 3 second then deceleration for the body would be equal to
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solution:
initial velocity, u= 40m/s
finl velocity, v= 10m/s
time taken, t= 3 sec.
acceleration, a=?
a= v-u/t
= 10-40/3
= -10/3= -3.3m/s^2
so, retardation = 3.3 m/s^2
______________
hope u like it☺☺
initial velocity, u= 40m/s
finl velocity, v= 10m/s
time taken, t= 3 sec.
acceleration, a=?
a= v-u/t
= 10-40/3
= -10/3= -3.3m/s^2
so, retardation = 3.3 m/s^2
______________
hope u like it☺☺
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