if a car increases speed by 10 km per hour then its takes 36 minutes less to cover a distance of 72 kilometre find the original speed of the car
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if a car increases speed by 10 km per hour then its takes 36 minutes less to cover a distance of 72 kilometre find the original speed of the car?????
let original speed is 's';
so ,(72/s-72/(s+10))=36/60
on soliving..
s(s+10)=1200
i.e s=30 kmph
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Step-by-step explanation:
let speed be X
uniform speed=72/X.........1
increased by 10=72/10-x.........2
from 1 and 2
72/X + 72/10-x=36
72(10-x)+72x/10x-x^2=36
720-72x+72x=36(10x-x^2)
720=360x-36x^2
36x^2-360x+720=0
(after reducing)
12x^2-120x+240=0
next to do formula method for factorization
36x^2-360
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