if a car is having speed 6 km at starting point of observation and 8km/h at the end with constant acceleration then calculate its speed at midpoint
Answers
Explanation:
hence,S1:s2:s3=2a:6a:10a
= 1:3:5.
Given : A car is having speed 6 km at starting point of observation and 8km/h at the end with constant acceleration
To Find : Speed at midpoint
Solution:
V = U + at
V = 8 km/hr
U = 6 km/hr
acceleration = a km/h²
V² - U² = 2aS
=> 8² - 6² = 2aS
=> S = 14/a
Distance covered = 14/a km
Distance covered till midpoint = 7/a km
speed at midpoint = x
x² - 6² = 2a (7/a)
=> x² = 36 + 14
=> x² = 50
=> x = 5√2 ≈ 7.071 km/hr
speed at midpoint is 5√2 ≈ 7.071 km/hr
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