If a car is traveling westward with a constant speed of 20 m/s overtakes another car which is moving at constant acceleration of 2m/s^2
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Let
t = Time interval for overtaking
Condition to overtake:
Distance travelled by first car = Total length of both cars + Distance travelled by second car
vt=(L+L) +1/2at^2
20t=2×4+1/2×2t^2
t^2−20t+8=0
t=0.4038
Distance used in overtaking:
d=vt
=20×0.4038
= 8.08 m
t = Time interval for overtaking
Condition to overtake:
Distance travelled by first car = Total length of both cars + Distance travelled by second car
vt=(L+L) +1/2at^2
20t=2×4+1/2×2t^2
t^2−20t+8=0
t=0.4038
Distance used in overtaking:
d=vt
=20×0.4038
= 8.08 m
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