Question

If a car is traveling westward with a constant speed of 20 m/s overtakes another car which is moving at constant acceleration of 2m/s^2

Answer 1

Let

t = Time interval for overtaking

Condition to overtake:

Distance travelled by first car = Total length of both cars + Distance travelled by second car
                                      
vt=(L+L) +1/2at^2

20t=2×4+1/2×2t^2

t^2−20t+8=0

t=0.4038

Distance used in overtaking:

d=vt   

=20×0.4038   

= 8.08 m