Question

If a car move 8cm due east .then it move and 6cm due North what is the distance cover by the car and its displacement?​

Answer 1

Answer:

22 meters

Explanation:

because the car went first east the he came back means 8 + 8 = 16 . Then he travel 6 cm to north means 16 + 6 = 22

Answer 2

Answer:

Explanation:

Distance covered = 8+6

=14cm

Displacement = shortest path = CA

Finding CA using pythagoras theorem

thus:

$CA^{2} =AB^{2} +BC^{2}$

$CA^{2} = 8^{2} + 6^{2} \\CA^{2} = 64 + 36\\CA^{2} = 100\\\sqrt{CA^{2} } =\sqrt{100} \\CA=10 CM$

Since displacement = CA=10 cm

Ans: Distance is 14 cm and displacement is 10 cm

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