Question

If a car moves from Odisha to Delhi covering 2000 km in 24 hours and return back to Delhi in 2 days. Find its average speed.

Answer 1

Answer:

Total Distance = 2000 km

Time Taken while going = 24 hours

Time Taken while returning = 2 days = 48 hours

The formula to calculate Average speed is given as:

$\boxed{ \textbf{Average Speed} = \dfrac{\textbf{Total Distance}}{\textbf{Total Time}}}$

Total Distance Travelled by the car is:

⇒ 2000 km + 2000 km = 4000 km

Total Time taken by the car is:

⇒ 24 hours + 48 hours = 72 hours

Hence the average speed of the car is:

$\implies \text{Average Speed} = \dfrac{4000\:\:km}{72\:\:hrs}\\\\\\\implies \boxed{ \textbf{Average Speed} = \bf{55.55\:\:km/hr}}$

Answer 2

QUESTION:-

If a car moves from Odisha to Delhi covering 2000 km in 24 hours and return back to Delhi in 2 days. Find its average speed.

EXPLANATION:-

We know that:-

Average speed=total distance/total time

Total distance=2000+2000=>4000 km  [SINCE IT RETURNS BACK ALSO]

Total times=24 hrs+48 hrs=>72 hrs(2 days=48 hrs)

Now let's calculate the average speed:-

Average speed=4000/72

Average speed=55.55 m/s or

55.55×5/18

=>15.5 m/s