If a car moving with 36 km/h increases its speed to 54 km/h in 10 seconds, find (i) acceleration and (ii) distance covered by the car in this time. *
3 points
If a car moving with 36 km/h increases its speed to 54 km/h in 10 seconds, find (i) acceleration and (ii) distance covered by the car in this time. *
3 points
An object travels 16 m in seconds and then another 16 m in 3 seconds. Is his motion uniform or non-uniform? *
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Ans. Initial velocity (u) = 36 km/h
When converted in m/s :-
Initial velocity (u) = 5/18×36
u = 10 m/s
Final velocity (v) = 54 km/h
When converted in m/s :-
Final velocity (v) = 5/18×54
v = 15 m/s
Time (t) = 10 s
(i) Acceleration (a) = (v-u)/t
a = (15-10)/10
a = 5/10
a = 0.5 m/s²
(ii) s = u×t + ½×a×t²
s = 10×10 + ½×0.5×10²
s = 100 + ½×0.5×10×10
s = 100 + 2.5×10
s = 100+25
Distance = 125 m
Sorry, but you have not given any time in third question for 1st motion but there is a 3 second time in the 2nd motion, so if any time except 3 seconds is given is given for 1st motion, it will be non-uniform motion and if the time for 1st motion is exactly 3 seconds it will be uniform motion.
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