If a car moving with 36 km/h increases its speed to 54 km/h in 10 seconds, find (i) acceleration and (ii) distance covered by the car in this time. *
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If a car moving with 36 km/h increases its speed to 54 km/h in 10 seconds, find (i) acceleration and (ii) distance covered by the car in this time. *
3 points
An object travels 16 m in seconds and then another 16 m in 3 seconds. Is his motion uniform or non-uniform? *
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A car traveling at a velocity of 10 m/s due north speeds up uniformly to a velocity of 25 m/s in 3s. Calculate the acceleration during this period. *
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Answer:
(I) a = 0.5 m/s^2
(ii) S= 125 m
Explanation:
i) a = (v-u) /t
u= 36 km/h = 36×5/18 = 10m/s
v= 54km/h = 54×5/18 = 15m/s
a = (15-10) / 10
a = 5/10 = 0.5 m/s^2
ii) v^2 =u^2 +2as
15^2 = 10^2 +2×0.5×S
225 - 100 = S
125 m = S
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