if a car moving with 36 km per hour increase its speed to 54 km per hour in 10 seconds find acceleration and distance covered by the car in its time
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Step-by-step explanation:
Vo = 36 km/h
Vf = 54 km/hr
t = 10 s × 1 hr/3600 s = 1/360 hr
SOLUTION:
a = (Vf - Vo)/t
a = (54 km/hr - 36 km/h)/1/360 hr
a = (18 km/hr)/ 1/360 hr
a = 6480 km/hr²
d = Vo(t) + 1/2 (a)(t²)
d = (36 km/hr × 1/360 hr) + 1/2 (6480 km/hr²)(1/360 hr)²
d = 1/10 km + 1/40 km
d = 0.125 km
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