Question

if a car moving with a speed of 25m/s stops due to application of brake for 5s what is the distance travelled before coming to rest ?

Answer 1

Answer:

Explanation:

v = u + at

0 = 25 + 5a

a = -5m/$s^{2}$

s = ut + $\frac{1}{2}$a$t^{2}$

  = 25 x 5  +  1/2 x -5 x $5^{2}$

  = 125 - 125/2

  = 125/2

  = 62.5 m