Question

 If a car of mass 2000 kg is moving with velocity 10 m/s is stopped in 2 seconds by applying the brakes then find the force applied by the brake?​

Answer 1

Answer:

The answer is -10000N

Explanation:

Mass of car=2000kg

initial velocity(u) = 10m/s

final  velocity(v) = 0m/s

time taken to stop the car (t)=2sec

first we will find the acceleration

acceleration (a)= (v-u)/t

                         a=(0-10)/2

                           =-5m/$s^{2}$

we know that ,

                                         force(f)=m*a

                                               =2000*(-5)N

                                               =-10000N

hence the car requare -10000N force to stop the car.

Answer 2

Given,

Mass of car =2000kg

Velocity=10m/s

Time =2 seconds

To find,

The Force applied by the brake

Solution,

We can simply solve this numerical problem by using the following processes

Now,

Mass of car = 2000kg

Velocity= 10m/s

Time= 2 sec

Final velocity = 0m/s

Force =?

(Here, all of the physical quantities I am in DI units, so no unit conversion is required )

According to the kinematics, we get the following mathematical expression:-

Retardation,a= v−u/t

a= 0-10/2 = −5m/s²

Now,

F=m×a

F= 2000×5= -10000N

This will be considered as the final result. The initial units are in the system, we have to use SI units for answers also and the SI unit of force is newton (N)

Hence the force applied by the brake will be -10000N