Question

If a car of mass 480 kg moving at speed 50 km/hr is stopped in 10s how much force is applied​ ?​

Answer 1

$GIVEN :-$

• Mass = 480 kg
• Initial velocity (u) = 50 km/hr = $50 \times \frac{5}{18}$ = $13.8 m/s^{2}$
• Final velocity (v) = 0
• T = 10 seconds

$TO \:FIND :-$

• Applied Force

$SOLUTION :-$

We know that,

★ Force = Mass x Acceleration

• Mass = 480 kg
• Acceleration = ?

Now, Finding Acceleration:

Acceleration = $u - \dfrac{v}{t}$

$\implies\:\:\dfrac{0 -13.8}{10 }$

$\implies\:\:-1.38m/s^{2}$

Now,

★ Force = Mass x Acceleration

$\implies\:\: 480 \times -1.38$

$\implies\:\: {\boxed{-662N}}$

Answer 2

Answer:

f=ma

=480×-50/10. a=v-u/t. v=o

=480×-5

-2400newton

Explanation:

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