Question

if a car of mass 480 kg moving at speed 50 kmph is stopped in 10s how much force is applied​

Answer 1

Q) If a car of mass 480 kg moving at speed 50 km/hr is stopped in 10s how much force is applied​ ?

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Answer :-

Given :-

M = 480 Kg

Initial velocity ( u ) = 50 km/hr = 50 x 5/18 = $13.8 m/s^{2}$

Final velocity ( v ) = 0

T = 10s

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To Find :-

How much Force is applied

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Solution :-

We know that

Force = Mass x Acceleration.

Here,

Mass = 480 kg.

Acceleration = ?

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Acceleration = u - v/t

= 0 - 13.8/10

= $-1.38m/s^{2}$

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Now,

Force = Mass x Acceleration

= 480 x ( -1.38 )

= -662N

Answer 2

Answer :-

F = -666.62 N

Given :-

m = 480 kg

u = 50 km /hr

= 50 × 5 /18

= 250/18

= 13.88 m/s

t = 10 s

To find :-

The frictional force applied.

Solution:-

First , find the retardation produced in the car.

→$a = \dfrac{0-13.88}{10}$

→$a = \dfrac{-13.88}{10}$

→$a = -1.388 m/s^2$

Now,

The magnitude of force applied on car will be given by :-

→$F = ma$

→$F = 480 \times - 1.388$

→$F = -666.62 N$

hence,

The force applied on the car will be -666.62 N in opposite direction.