If a car of mass 900 kg stops from a speed of 90kmph in just 10 seconds, then the force responsible for stopping the car is _______ (in N)
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Given:-
- Mass of car ,m = 900kg
- Initial velocity ,u = 90km/h
- Final velocity ,v = 0m/s
- Time taken ,t = 10s
To Find:-
- Force responsible for stopping the car,F.
Solution:-
Unit Conversion
→ 90km/h = 90×5/18 = 25m/s
Firstly we have to calculate the acceleration of the car.
Rate of change of velocity at per unit time is called acceleration.
→ a = v-u/t
Substitute the value we get
→ a = 25-0/10
→ a = 25/10
→ a = 2.5m/s²
Now we know that Force is the product of mass and acceleration
→ F = m×a
Substitute the value we get
→ F = 900×2.5
→ F = 2250N
∴ The force responsible for stopping car is 2250 Newton.
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