Question

If a Car registration number have four symbols, the first two of which are letters and the remainder digits, how many different registration numbers can be made?​

Answer 1

In reality there are likely to be some constraints, such as not using the letters I, O and Q due to possible confusion with 1 and 0. But in theory there are 26 possibilites for each of the letters and 10 possibilities for each of the digits.

So the number of possible combinations is;

26 x 26 x 10 x 10 = 67600

Answer 2

Answer:

Number of registration numbers are $26^{2} \times10^{2}$ or $67600$.

Step-by-step explanation:

The total number of arrangements of $2$  letters of English alphabet are =$26\times26$

The total number of arrangements of remainder digits are=$10\times10$

$\therefore$ The total number of vehicles with distinct registration number=$=26\times26\times10\times10\\=26^{2}\times10^{2}\\=67600$

Hence, Number of registration numbers are $26^{2} \times9\times10^{3}$.

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