Question

If a car runs at 45km/hr it reaches its destination late by 10 min but if runs at 60km/hr it is late by 4min. What is the correct time for the journey?​

Answer 1

Answer:

Step-by-step explanation:

Distance = diff in time *(S1*S2)/S1-S2

D=[10-4]/60hr * (45*60)/[60-45] = 6/60 * 45*60/15 ==>18km

time T=D/S(take any one of the speed) 18/45 =2/5hrs =  2/5*60=24min

then correct time is 24-10=14mins.

Answer 2

The correct time for the journey is 0.23 hours.

Given,

A car runs at 45km/hr it reaches its destination late by 10 min but if runs at 60km/hr it is late by 4min

To Find,

The correct time of the journey.

Solution,

For car A

Speed = 45 km/hr

Time = 10 min = 10/60 = 1/6 hr

For car B

Speed = 60 km/hr

Time = 4/60 = 1/15 hr

Let us assume that the correct time is t hrs.

So,

For car A

Distance = speed *time = 45(t+1/6)

For car B

Distance = speed*time = 60(t+1/15)

Now, equating the distances as it will remain the same in both cases.

45(t+1/6) = 60(t+1/15)

45t+45/6 = 60t+60/15

15t = 45/6-60/15

15t = 3.5

t = 0.23 hr

Hence, the correct time for the journey is 0.23 hours.

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