Question

if a car slows down from 27.7m/s to 10.9m/s in 2.37s,what is its acceleration​

Answer 1

Answer:

The car slows down from initial velocity 'u' = 27.7 m/s

to final velocity 'v' =10.9 m/s in time 't' = 2.37 secs.

v = u + f* t, where, f = acceleration and decceleration in this case in m/sec^2

10.9 = 27.7 + f x 2.37 or, f = (10.9 - 27.7) / 2.37 = -16.8 / 2.37 = -7.0886

So acceleration = -7.09 m/sec^2 or, decceleration is 7.09 m/sec^2.

Answer 2

Answer:

acceleration=change in velocity/time

=>v-u/t

10.9-27.7/2.37

-84. 5/237/100

-560/79

therefore the acceleration=-7.088m/s^2