if a car start from rest and acquires a velocity of 90 km/hr in 5 min. calculate acceleration and distance covered
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Answered by
2
Answer:
0.8 m/s^2 acceleration and 7500m distance covered by the car
Step-by-step explanation:
v = 90 km/hour = 90 x 1000/3600 = 25 m/sec
t = 5 min x 60 secs = 300 secs
s = vt = 25 x 300 = 7500 m
a = v/t = 25/300 = 5/6 = 0.8 m/s^2
Answered by
2
Answer:
0.8 .................,......
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