Question

If a car starts from a towards b with some velocity. Due to some problem in the engine after traveling 30km, the car goes with 4/5 th of its actual velocity .The car reaches b 45 min later to the actual time. If the car engine fails after traveling 45km, the car reaches the destination b 36min late to the actual time what is the initial velocity of car and what is the distance between a and b in km

Answer 1

Solution

Let the distance between A and B is x and the velocity initially is v
then according to the given conditions
[30/v]+[(x-30)/(4v/5)] = [x/v]+3/4 here 3/4 is for 45 minute
[45/v]+[(x-45)/(4v/5)] = [x/v]+3/5 here 3/5 is for 36 minute
on solving we will get (x-30)/v = 3 and (x-45)/v = 12/5
or x-30 = 3v and x-45 = 12v/5 or x = 105 and v = 25