If a car starts from rest has an acceleration that increases linearly with time as a = 2t here t is in second then the average velocity for first 3 seconds
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Answered by
1
Answer:
9 m/s
Explanation:
since a=2t
implies ( dV/ dt ) = 2t
dV = 2t dt
on integrating we get
V = t^2 + c
on applying limits from 0 - 3
V = 3^2 - 0^2
= 9
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