If a car travels (2/5th) of the total distance with speed of 10 m/sec and (3/5th) of the distance with speed 20 m/sec. The average speed is given by
Answers
Explanation:
Hope this will help you
Given: A car travels (2/5th) of the total distance with speed of 10 m/sec and (3/5th) of the distance with speed 20 m/sec.
To find: Average speed of the car
Explanation: Let the total distance covered be s.
During first part of the journey, 2/5 of the distance is covered.
Distance covered= 2s/5
Time taken
= Distance covered/ Speed
= (2s/5) / 10
= s/25
During second part of the journey, 3/5 of the distance is covered.
Distance covered= 3s/5
Time taken
= Distance covered/ Speed
= (3s/5) / 20
= 3s/100
Total time taken
= s/25 + 3s/100
= 4s+3s/100
= 7s/100
Average speed is equal to the total distance covered by total time taken to complete this journey.
Average speed
= Total distance/ Total time taken
= s / (7s/100)
= 100/7
= 14.285 m/s
The average speed of the car is 14.285 m/s.